Respuesta :
Answer : The unknown gas is, NO
Solution :
According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.
[tex]R\propto \sqrt{\frac{1}{M}}[/tex]
or,
[tex](\frac{R_2}{R_1})=\sqrt{\frac{M_1}{M_2}}[/tex] ..........(1)
where,
[tex]R_1[/tex] = rate of effusion of unknown gas = 31.50 mL/min
[tex]R_2[/tex] = rate of effusion of [tex]O_2[/tex] gas = 30.50 mL/min
[tex]M_1[/tex] = molar mass of unknown gas = ?
[tex]M_2[/tex] = molar mass of [tex]O_2[/tex] gas = 32 g/mole
Now put all the given values in the above formula 1, we get:
[tex](\frac{30.50mL/min}{31.50mL/min})=\sqrt{\frac{M_1}{32g/mole}}[/tex]
[tex]M_1=30.0g/mol[/tex]
From the this we conclude that the unknown gas is, NO that has 30.0 g/mol molar mass.
Hence, the unknown gas is, NO
