When responding to sound, the human eardrum vibrates about its equilibrium position. Suppose an eardrum is vibrating with an amplitude of 7.5 x10-7 m and a maximum speed of 3.3 x10-3 m/s. (a) What is the frequency (in Hz) of the eardrum's vibrations

Respuesta :

Answer:

f = 700 Hz

Explanation:

given

amplitude =[tex]a= 7.5 \times 10^{-7} m[/tex]

speed v =[tex]3.3 \times 10^{-3}[/tex] m/s

for (a)

we know [tex]v_{max} = a\omega[/tex]

and [tex]\omega = 2\pi f[/tex]

we get

[tex]v_{max} = a( 2 \pi f)[/tex]

[tex]f = \frac{v_{max}}{2 \pi a}[/tex]

[tex]f = \frac{ 3.3 \times 10^{-3}}{ 2 \times 3.14 \times 7.5 \times 10^{-7}}[/tex]

[tex]f = 700 Hz[/tex]