Respuesta :
Answer: 89.9
Explanation:-
The balanced chemical equation is :
[tex]NaOH(aq)+HA(aq)\rightarrow NaAaq)+H_2O(l)[/tex]
To calculate the moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution in ml}}[/tex] .....(1)
Molarity of [tex]NaOH[/tex] solution = 0.35 M
Volume of solution = 50.80 ml
Putting values in equation 1, we get:
[tex]0.35M=\frac{\text {moles of} NaOH\times 1000}{50.80ml}[/tex]
[tex]{\text {moles of} NaOH=0.0178[/tex]
According to stoichiometry:
1 mole of NaOH reacts with = 1 mole of HCl
Thus 0.0178 moles of NaOH reacts with = [tex]\frac{1}{1}\times 0.0178=0.0178[/tex] moles of HCl
mass of HCl = [tex]moles\times {\text {Molar mass}}[/tex]
1.6g= [tex]0.0178\times {\text {Molar mass}}[/tex]
Molar mass of HCl = 89.9
The molar mass (g/mol) of the acid is 89.9
The molar mass of the monoprotic acid would be 89.99 g/mol
First, let us look at the equation of the reaction:
HA + NaOH ---> NaA + H2O
Mole ratio of acid to base = 1:1
Volume of NaOH required = 50.80 mL
Molarity of NaOH = 0.35 M
Mole of NaOH = molarity x volume
= 0.35 x 50.80/1000
= 0.01778 mole
Since the mole ratio according to the balance equation is 1:1, it means that the mole of the monoprotic acid would also be 0.01778.
Thus, molar mass of the monoprotic acid = mass/mole
= 1.6/0.01778
= 89.99 g/mol
More on molar mass can be found here: https://brainly.com/question/12127540
