Answer:
Average force exerted by club on the ball is 3375 N
Explanation:
We have given mass of the ball m = 45 gram = 0.045 kg
Speed acquires by the ball v = 75 m/sec
It is given that ball is in contact with club for 0.001 sec
Momentum of the ball [tex]P=mv=0.045\times 75=3.375kgm/sec[/tex]
We have to find the average force
Force is equal to rate of change of momentum
So force [tex]F=\frac{dP}{dt}=\frac{3.375}{0.001}=3375N[/tex]
So average force exerted by club on the ball is 3375 N