Answer:
V₁ = 31.5 mL
Explanation:
Given data:
Initial molarity = 2.50 M
Initial volume required = ?
Final molarity = 0.150 M
Final volume = 525 mL
Solution:
Formula:
M₁V₁ = M₂V₂
M₁ = Initial molarity
V₁ = Initial volume
M₂ = Final molarity
V₂ = Final volume
Now we will put the values in formula.
2.50 M × V₁ = 0.150 M × 525 mL
V₁ = 0.150 M × 525 mL/ 2.50 M
V₁ = 78.75 M.mL/ 2.50 M
V₁ = 31.5 mL
The mL of a 2.50 M NaOH solution are required should be V₁ = 31.5 mL.
Since
Initial molarity = 2.50 M
Final molarity = 0.150 M
Final volume = 525 mL
So here the following formula should be used
M₁V₁ = M₂V₂
here,
M₁ = Initial molarity
V₁ = Initial volume
M₂ = Final molarity
V₂ = Final volume
So,
2.50 M × V₁ = 0.150 M × 525 mL
V₁ = 0.150 M × 525 mL/ 2.50 M
V₁ = 78.75 M.mL/ 2.50 M
V₁ = 31.5 mL
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