Answer:
Q = 63,827.5 W
Explanation:
Given:-
- The dimensions of plate A = ( 10 mm x 1 m )
- The fluid comes at T_sat , 1 atm.
- The surface temperature, T_s = 75°C
Find:-
Determine the total condensation rate of water vapor onto the front surface of a vertical plate
Solution:-
- Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.
h = 255,310 W /m^2.K
- The rate of condensation (Q) is given by Newton's cooling law:
Q = h*As*( T_sat - Ts )
Q = (255,310)*( 0.01*1)*( 100 - 75 )
Q = 63,827.5 W
Answer:
Q = 63,827.5 W
Explanation:
From the questions given, we recall the following,
The dimensions of vertical plate A = ( 10 mm x 1 m )
The fluid comes at T_sat, 1 atm.
The surface temperature pressure maintained T_s = 75°C
Thus we determine,
The total rate of condensation of water vapor onto the front surface of a vertical plate
Assuming drop-wise condensation the heat transfer coefficient for water is given by
Griffith's empirical relation for T_sat = 100°C.
Then
h = 255,310 W /m^2.K
The rate of condensation (Q) is stated by Newton's cooling law:
Q = h x As x ( T_sat - Ts )
Q = (255,310)x ( 0.01 x 1)x ( 100 - 75 )
Therefore
Q = 63,827.5 W
