Answer:
C) [tex]C=40[/tex]°, [tex]a= 10.1[/tex] , [tex]c=6.72[/tex]
Step-by-step explanation:
[tex]C= 180-105-35[/tex]
[tex]C=40[/tex]°
Next using Sine rule,
[tex]\frac{a}{sinA}=\frac{c}{sinC} =\frac{b}{sinB}[/tex]
where [tex]A=105[/tex]°, [tex]C=40[/tex]° , [tex]B =35[/tex]° and [tex]b = 6[/tex].
[tex]\frac{a}{sin105}=\frac{c}{sin40} =\frac{6}{sin35}[/tex]
Solve for a and c
[tex]a= \frac{6}{sin35} (sin105)[/tex]
[tex]a= 10.1[/tex]
[tex]c = \frac{6}{sin35} (sin40)[/tex]
[tex]c=6.72[/tex]
