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A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C. What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 °C, if the amount of gas does not change?

Respuesta :

Answer:

The final volume of the bubble [tex]V_{2}[/tex] = 625 ml = 0.625 L

Explanation:

[tex]V_{1}[/tex] = 0.25 L = 250 ml

[tex]P_{1}[/tex] = 2.4 atm

[tex]T_{1}[/tex] = 15 °c = 288 K

[tex]P_{2}[/tex] = 1 atm

[tex]T_{2}[/tex] = 27 °c = 300 K

Mass of the gas is constant.

We know that

[tex]P_{1} \frac{V_{1}}{T_{1} } = P_{2} \frac{V_{2}}{T_{2} }[/tex]

Put all the values in above equation we get

[tex]2.4 (\frac{250}{288} )= 1 (\frac{V_{2} }{300} )[/tex]

[tex]V_{2}[/tex] = 625 ml = 0.625 L

This is the final volume of the bubble.

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