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A constant torque is applied to a rigid wheel whose moment of inertia is 2.0 kg · m2 around the axis of rotation. If the wheel starts from rest and attains an angular velocity of 25.0 rad/s in 13.0 s, what is the applied torque (in N · m)? (Indicate the direction with the sign of your answer.)

Respuesta :

Answer:

The applied torque is 3.84 N-m.      

Explanation:

Given that,

Moment of inertia of the wheel is [tex]2\ kg-m^2[/tex]

Initial speed of the wheel is 0 (at rest)

Final angular speed is 25 rad/s

Time, t = 13 s

The relation between moment of inertia and torque is given by :

[tex]\tau=I\alpha \\\\\tau=I\times \dfrac{\omega_f}{t}\\\\\tau=2\times \dfrac{25}{13}\\\\\tau=+3.84\ N-m[/tex]

So, the applied torque is 3.84 N-m.

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