contestada

A 2100 kg truck is traveling east through an intersection at 2.0 m/s when it is hit simultaneously from the side and the rear. (Some people have all the luck!) One car is a 1200 kg compact traveling north at 5.0 m/s. The other is a 1500 kg midsize traveling east at 10 m/s. The three vehicles become entangled and slide as one body. What is their velocity (magnitude and direction) just after the collision?

Respuesta :

Answer:

speed is [tex]3.41[/tex]   meter per second and direction is [tex]66.25[/tex]   degrees

Explanation:

As per the conservation of momentum theory, Initial momentum is equal to final momentum

[tex]Pi_{1200} + Pi_{1500} + Pi_{2100} = Pf_{1200} + Pf_{1500} + Pf_{2100} \\m_{1200} * v_{1200} + m_{1500} * v_{1500} + m_{2100} * v_{2100} = [ m_{1200} + m_{1500} + m_{2100}] * V_f[/tex]

Substituting the given values we get

Velocity in horizontal direction

[tex]1200 * 5 + 0 + 2100 * 2 = 4800 * V_{fx}\\V_{fx} = 1.375 \frac{m}{s}[/tex]

Velocity in vertical direction

[tex]1500*10 = 4800 * V_{fx}\\V_{fx} = 3.125 \frac{m}{s}[/tex]

Final velocity

[tex]\sqrt{1.375 ^2 + 3.125^2}\\3.41=[/tex]

Direction of the  velocity

[tex]\alpha = tan^{-1} \frac{3.125}{1.375} \\= 66.25[/tex]

So speed is [tex]3.41[/tex]   meter per second and direction is [tex]66.25[/tex]   degrees

Otras preguntas