Answer: The new pressure, if volume and amount of gas do not change is 2.40 atm
Explanation:
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are the initial pressure and temperature of the gas.
[tex]P_2\text{ and }T_2[/tex] are the final pressure and temperature of the gas.
We are given:
[tex]P_1=3.60atm\\T_1=27^0C=(27+273)K=300K\\P_2=?\\T_2=-73.0^0C=(273-73)=200K[/tex]
Putting values in above equation, we get:
[tex]\frac{3.60}{300K}=\frac{P_2}{200K}\\\\P_2=2.40atm[/tex]
Thus the new pressure, if volume and amount of gas do not change is 2.40 atm
