Answer:
change in mass = 2.41*10^{8}kg
Explanation:
The change in the mass can be computed by using the relation
[tex]E=\Delta mc^2\\\Delta m=\frac{E}{c^2}[/tex](1)
That is, the energy liberated comes from the mass of the nuclear fuel. The energy generated in one year is
[tex]E=Pt=2.3*10^{9}\frac{J}{s}*1 year*\frac{365.25 day}{1 year}*\frac{24h}{1 day}*\frac{3600s}{1h}=7.25*10^{16}J[/tex]
Hence, by replacing in the equation (1) you have (c=3*10^{8}m/s)
[tex]\Delta m=\frac{7.25*10^{16}J}{3*10^{8}\frac{m}{s}}=2.41*10^{8}kg[/tex]
HOPE THIS HELPS!!
Answer:
The change in the mass of the nuclear fuel due to the energy being taken from the reactor is 0.81 kg
Explanation:
Given:
P = power 2.3x10⁹W
The energy taking from the reactor is:
E = P * t = 2.3x10⁹ * 365 * 24 * 60 * 60 = 7.25x10¹⁶J
The change in the mass is:
E = Δm * c²
Where c is speed of light in vacuum
Δm = E/c² = 7.25x10¹⁶/(3x10⁸)² = 0.81 kg
