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A plane crashes into the inside of a mountain if the crash place over 9 minutes and the planes velocity before the crash was 2000 yards per second what is the deceleration of the plane

Respuesta :

Answer:

The deceleration of the plane is [tex]3.38\ m/s^2[/tex].

Explanation:

Given that,

The planes velocity before the crash was 2000 yards per second

1 yards per second = 0.9144 m/s

2000 yards per second = 1828.8 m/s  

Finally it crashes, its final speed will be 0.

It takes 9 minutes or 540 seconds. It will decelerate as the final speed is less than initial speed. So,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-1828.8}{540}\\\\a=-3.38\ m/s^2[/tex]

So, the deceleration of the plane is [tex]3.38\ m/s^2[/tex].