A street light is at the top of a 11 foot tall pole. A 6 foot tall woman walks away from the pole with a speed of 4 ft/sec along a straight path. How fast is the tip of her shadow moving when she is 45 feet from the base of the pole

Respuesta :

Answer:

8.8ft/s

Step-by-step explanation:

Height of pole=11 foot

Height of man=6  foot

Let x be the distance of man from the pole and y be the distance of tip of shadow from the base of the pole.

[tex]\frac{dx}{dt}=4 ft/s[/tex]

Two right  triangles are similar then the ratio of their corresponding sides are equal

[tex]\frac{6}{11}=\frac{y-x}{y}[/tex]

[tex]6y=11y-11x[/tex]

[tex]11x=11y-6y=5y[/tex]

Differentiate w.r.t t

[tex]11\frac{dx}{dt}=5\frac{dy}{dt}[/tex]

[tex]11\times 4=5\frac{dy}{dt}[/tex]

[tex]\frac{dy}{dt}=\frac{11\times 4}{5}=8.8ft/s[/tex]

Hence, the tip of her shadow is moving at the rate 8.8ft/s when she is 45 feet from the  base of the pole

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