Answer:
The magnitude of [tex]V_{2}[/tex] is 4 V and phase of input voltage is zero
Explanation:
Given:
Output voltage [tex]V_{out} = 17.33[/tex]
Resistance [tex]R_{1} = 3[/tex] kΩ
Voltage gain [tex]A_{v} = 4.33[/tex]
For finding feedback resistance we use gain equation
Gain equation for non inverting op-amp is given by,
[tex]A_{v} = 1+\frac{R_{f} }{R_{1} }[/tex]
[tex]4.33 = 1+ \frac{R_{f} }{3 k }[/tex]
[tex]R_{f}[/tex] ≅ 10 kΩ
For finding input voltage we use,
[tex]A_{v} = \frac{V_{out} }{V_{2} }[/tex]
[tex]V_{2} = \frac{17.33}{4.33}[/tex]
[tex]V_{2} = 4[/tex] V
The Phase of [tex]V_{2}[/tex] is zero because output voltage phase is 360°
Therefore, the magnitude of [tex]V_{2}[/tex] is 4 V and phase of input voltage is zero
