Answer:
The percent increase in iron = 50 %
Step-by-step explanation:
Initial amount of iron per serving = 1.2 mg
After an increase the amount of iron per serving = 1.8 mg
Increase in the amount of iron per serving = 1.8 - 1.2 = 0.6 mg
Percent increase in iron is calculated as
[tex]% increase = \frac{Final amont - initial amount }{initial amount}[/tex][tex]Change = \frac{Final \ amount - initial \ amount }{initial \ amount} (100)[/tex]
Put the values in above formula we get
[tex]\frac{0.6}{1.2} (100)[/tex] = 50 %
Therefore the percent increase in iron = 50 %
