Answer:
The mean of the average scores will be 501 and the standard deviation will be [tex]s = \frac{112}{\sqrt{100}} = 11.2[/tex]
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that
For the population, mean 501 and standard deviation 112.
SRS of 100.
So, by the Central Limit Theorem
The mean of the average scores will be 501 and the standard deviation will be [tex]s = \frac{112}{\sqrt{100}} = 11.2[/tex]