The molecular formula of the compound with an empirical formula of C₂H₅O₂ and a molar mass of 122.11 g/mol is C₄H₁₀O₄.
First, we need to determine the molar mass of the empirical formula.
[tex]M(C_2H_5O_2) = 2M(C) + 5M(H)+2M(O)= 2(12.01 g/mol) + 5(1.01 g/mol)+2(16.00 g/mol) = 61.07 g/mol[/tex]
Then, we will calculate "n", which is the quotient between the molar mass of the molecular formula and the molar mass of the empirical formula.
[tex]n = \frac{122.11g/mol}{61.07g/mol} \approx 2[/tex]
Finally, we will multiply the empirical formula by "n" to get the molecular formula.
[tex]C_2H_5O_2 \times 2 = C_4H_1_0O _4[/tex]
The molecular formula of the compound with an empirical formula of C₂H₅O₂ and a molar mass of 122.11 g/mol is C₄H₁₀O₄.
You can learn more about empirical formulas here: https://brainly.com/question/1363167
