Answer:
The heat loss Q = 1.6 KJ
Explanation:
Mass of the ice = 71 gm
Heat of fusion for water is ΔH = 6.02 [tex]\frac{KJ}{mol}[/tex]
No. of moles of ice
[tex]n = \frac{m}{M}[/tex]
[tex]n = \frac{71}{267}[/tex]
n = 0.266
Now Heat loss is
Q = ΔH × n
Q = 0.266 × 6.02
Q = 1.6 KJ
Therefore the heat loss Q = 1.6 KJ