Answer:
Pressure=3.91atm
Explanation:
As given in the question that gas is ideal so
we can use Ideal gas equation
[tex]PV=nRT[/tex]
volume of gas is not given directly but volume of container is given and we know gas takes the volume in which they are kept.
therefore mole remains contant
P1=2.5 atm
V1=2L
T1=320K
P1=?
V1=1L
T1=250K
[tex]2.5\times 2V=nR \times 320[/tex]..............(1)
[tex]P\times V=nR \times 250[/tex]................(2)
eqn2/eqn1
[tex]\frac{P}{2.5} \times \frac{1}{2} =\frac{250}{320}[/tex]
Pressure=3.91atm
