Answer:
The final velocity after the collision is 0.27 m/s.
Explanation:
Given that,
Mass of tiger, m = 0.195 kg
Initial speed of tiger model, v = 0.75 m/s
Mass of another clay model, m' = 0.335 kg
Initially, second model is at rest, v' = 0
We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :
[tex]mv+m'v'=(m+m')V\\\\V=\dfrac{mv+m'v'}{(m+m')}\\\\V=\dfrac{0.195\times 0.75}{(0.195 +0.335 )}\\\\V=0.27\ m/s[/tex]
So, the final velocity after the collision is 0.27 m/s.
