Answer:
The magnitude of the new magnetic force on each wire will be 4 times of the initial force.
Explanation:
When two long parallel wires carry unequal currents, the magnetic force acting on two wires per unit of length is given by :
[tex]\dfrac{F}{l}=\dfrac{\mu_o I_1I_2}{2\pi r}[/tex]
r is distance from wires
If the current in both wires is now doubled, new force per unit length is given by :
[tex](\dfrac{F}{l})'=\dfrac{\mu_o (2I_1)(2I_2)}{2\pi r}\\\\(\dfrac{F}{l})'=4\times \dfrac{\mu_o I_1I_2}{2\pi r}\\\\(\dfrac{F}{l})'=4\times \dfrac{F}{l}[/tex]
So, the magnitude of the new magnetic force on each wire will be 4 times of the initial force.
