Answer:
The standard error of the mean for this sample is 9.1
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation, which is also called standard error of the mean, [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
[tex]\sigma = 63.7, n = 49[/tex]
So
[tex]s = \frac{63.7}{\sqrt{49}} = 9.1[/tex]
The standard error of the mean for this sample is 9.1
