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Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60 kg and has a horizontal velocity of 5 m/s just before the grab.Another acrobat has a mass of 50 kg and has a horizontal velocity of -3 m/s just before the grab.Their horizontal velocity immediately after they grab onto each other is:

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lublana

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat,[tex]m_1=60 kg[/tex]

Mass of another acrobat,[tex]m_2=50 kg[/tex]

[tex]v_2=-3 m/s[/tex]

[tex]v_1=5 m/s[/tex]

We have to find their  velocity immediately after they grab  onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

[tex]m_1v_1+m_2v_2=(m_1+m_2)V[/tex]

Substitute the values

[tex]60\times 5+50(-3)=(60+50)V[/tex]

[tex]300-150=110V[/tex]

[tex]V=\frac{300-150}{110}=1.36m/s[/tex]

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