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A 1400 kg car is traveling on a level road at a constant speed of 26.8 m/s (60 milesper hour.) The drag force exerted by air on the car and the frictional force exerted by theroad on the car’stires add to give a net force of 680N pointing opposite to the direction ofthe car’s motion. What is the rate of work done (power) by the air and the road on thecar?

Respuesta :

Answer:power 18Kw

Explanation:

Data given

Mass of car m= 1400kg

Speed=26.8m/s

Drag force F=680N

Recall power is the rate if doing work

Ie power= Work/time

Also work w is given by force*distance cos A

Hence power = fdcosA/ t= fvcosA

We're v is the velocity

Power= 680*26.8*cos180°= 18*10^3W divide by 1000

Power =18kw

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