Answer:
The ratio of gravitational force is 0.8920
Explanation:
The gravitational force is given by F=[tex]\frac{GMm}{R^{2} }[/tex]
The gravitational force on the astronaut when he is in
Surface of earth F₁ =[tex]G\frac{Mm}{R^{2} }[/tex] eqn 1
Circular orbit F₂ =[tex]G\frac{Mm}{(R+h)^{2} }[/tex] eqn 2
Where M is mass of earth,
m is mass of astronaut
R is radius of earth 6380 km,
h is the distance from earth surface 315 km.
Dividing eqn 1 and 2
= [tex]\frac{R^{2} }{(R+h)^{2} }[/tex]
=[tex]\frac{(6380)^{2} }{(6380+315)^{2} }[/tex]
=0.8920
The ratio of gravitational force is 0.8920
