A charged particle is injected at 265 m/s into a 0.0891 ‑T uniform magnetic field perpendicularly to the field. The diameter of its orbit is measured and found to be 0.0383 m. What is the charge–to–mass ratio of this particle?

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aristeus aristeus · Answer 1 · 2020-04-11T04:48:09+02:00

Answer:

Charge to mass ratio of particle is 155309.98

Explanation:

We have given velocity of charged particle v = 265 m/sec

Magnetic field B = 0.0891 T

Diameter of the orbit is given d = 0.0383 m

So radius of the orbit [tex]r=\frac{d}{2}=\frac{0.0383}{2}=0.0191m[/tex]

We have to find the charge to mass ratio of particle

Radius of the orbit is equal to [tex]r=\frac{mv}{qB}[/tex]

0.0191=\frac{m\times 265}{q\times 0.0891}

[tex]\frac{m}{q}=6.44\times 10^{-6}[/tex]

[tex]\frac{q}{m}=155309.98[/tex]

So charge to mass ratio of particle is 155309.98

andromache andromache · Answer 2 · 2022-03-17T18:42:23+01:00

The charge–to–the mass ratio of this particle is 155309.98.

Since velocity of charged particle v = 265 m/sec

Magnetic field B = 0.0891 T

The diameter of the orbit is given d = 0.0383 m

So here radius should be half of diameter = 0.0191m

Now the charge to mass ratio should be

[tex]0.0191=\frac{m\times 265}{q\times 0.0891}[/tex]

m/q = 6.44*10^-6

So, it should be 155309.98.

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