Respuesta :
Answer:
Damping constant is equal to [tex]2\sqrt{43}[/tex]
Explanation:
We have given mass m = 1 kg
Spring constant is given [tex]k=43kg/sec^2[/tex]
For critical damping [tex]\zeta =1[/tex]
We have to find the damping constant
Damping constant is equal to [tex]\zeta =\frac{c}{2\sqrt{\frac{k}{m}}}[/tex]
So [tex]1 =\frac{c}{2\sqrt{\frac{k}{m}}}[/tex]
[tex]c=2\sqrt{\frac{k}{m}}[/tex]
[tex]=2\sqrt{\frac{43}{1}}=2\sqrt{43}[/tex]
So damping constant is equal to [tex]2\sqrt{43}[/tex]
Damping constant that would produce critical damping is 2√43.
Damping constant:
What information do we have?
Mass of spring (m) = 1 kg
Spring constant (k) = 43 kg/s²
Velocity = 5 m/s
Dumping constant = c = [tex]2\sqrt{\frac{k}{m} }[/tex]
Dumping constant = c = [tex]2\sqrt{\frac{43}{1} }[/tex]
Dumping constant = c = 2√43
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