Answer:
Box A
Explanation:
Let mass of each wooden box =m
Density of box A=[tex]\rho_A[/tex]
Density of box B =[tex]\rho_B[/tex]
[tex]\rho_A<\rho_B[/tex]
Density,[tex]\rho=\frac{m}{V}[/tex]
[tex]V_A=\frac{m}{\rho_A}[/tex]
[tex]V_B=\frac{m}{\rho_B}[/tex]
Density of inversely proportional to volume.
The volume of box with smaller density is larger than the volume of box with large density.
[tex]V_A>V_B[/tex]
When the boxes are submerged under water.
Then, the buoyant force=[tex]\rho_l Vg[/tex]
Where V=Volume of displace fluid.
[tex]\rho=[/tex]Density of fluid
Buoyant force of box A=[tex]\rho_lV_Ag[/tex]
Buoyant force of box B=[tex]\rho_lV_Bg[/tex]
Force=Buoyant force
[tex]ma_A=\rho_lV_Ag[/tex]
[tex]ma_B=\rho_lV_Bg[/tex]
Acceleration is directly proportional to volume.
Therefore,the box with large volume has greater acceleration.
Hence, the box A has greater acceleration.
Answer:
Explanation:
Let boxes A and B has equal mass of M and volume be Va and Vb
their density be da and db
given da < db
M / Va < M/Vb
Va> Vb
Buoyant force on box A in water = weight of displaced water
= volume of displaced water x density of water x g
= Va x d x g , d is density of water
Aa = acceleration on box A
= buoyant force on A / mass of A
= Va x d x g / M
Similarly acceleration on box B
Ab = Va x d x g / M
Since Va > Vb
Aa > Ab
So box A will have greater acceleration.
