Answer:
[tex]H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}[/tex]
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 206 mg
Sample mean, [tex]\bar{x}[/tex] = 217.5 mg
Sample size, n = 14
Sample standard deviation, s = 14.9 mg
Claim:
The mean sodium content for the sports drink is not 206 mg. It is different than 206 mg.
Thus, we design the null and the alternate hypothesis
[tex]H_{0}: \mu = 206\text{ mg}\\H_A: \mu \neq 206\text{ mg}[/tex]
We use two-tailed t test to perform this hypothesis.