The distance between two protons to generate 950N of force is 0.49 X 10⁻¹⁵ m
Explanation:
Given:
Mass of man, m = 100 kg
Force between man and earth = 980 N
Charge of proton, q = 1.6 X 10⁻¹⁹C
Same force is generated between them
Distance between two protons, r = ?
According to Coulomb's law:
[tex]F = k\frac{q_1q_2}{r^2}[/tex]
where,
k is Coulomb's constant
k = 9 X 10⁹ Nm²/C²
According to the question:
[tex]950 = k\frac{q_1q_2}{r^2}[/tex]
Solving the equation:
[tex]950 = (9X10^9) X\frac{(1.6 X 10^-^1^9 X 1.6 X 10^-^1^9)}{r^2} \\\\r^2 = \frac{(9 X 10^9) (1.6 X 10^-^1^9 X 1.6 X 10^-^1^9)}{950} \\\\r^2 = 0.024 X 10^-^2^9\\\\r^2 = 0.24 X 10^-^3^0\\\\r = 0.49 X 10^-^1^5 m[/tex]
Therefore, the distance between two protons to generate 950N of force is 0.49 X 10⁻¹⁵ m
The distance between two protons will be "0.49 × 10⁻¹⁵ m". To understand the calculation, check below.
According to the question,
Man's mass, m = 100 kg
Force, F = 980 N
Proton's charge, q = 1.6 × 10⁻¹⁹ C
Coulomb's constant, k = 9 × 10⁹ Nm²/C²
By using the Coulomb's law,
→ F = k [tex]\frac{q_1 q_2}{r^2}[/tex]
By substituting the values,
950 = 9 × 10⁹ × [tex]\frac{1.6\times 10^{-19}\times 1.6\times 10^{-19}}{r^2}[/tex]
By applying cross-multiplication,
r² = [tex]\frac{(9\times 10^9)(1.6\times 10^{-19}\times 1.6\times 10^{-19})}{950}[/tex]
= 0.024 × 10⁻³⁰
r = 0.49 × 10⁻¹⁵ m
Thus the approach above is appropriate,
Find out more information about force here:
https://brainly.com/question/66110
