Answer:
The answer to your question is below
Explanation:
1.-
Data
[HCl] = 0.3 N
Volume a = 6 ml
[NaOH] = ?
Volume b = 12 ml
Formula
[HCl] x Volume a = [NaOH] x Volume b
-Solve for [NaOH]
[NaOH] = [HCl] x Volume a / Volume b
-Substitution
[NaOH] = 0.3 x 6 / 12
-Simplification
[NaOH] = 0.15 N
2.-
Data
[H₂SO₄] = 7 N
Volume a = 12 ml
[KOH] = 3 N
Volume b = ?
Formula
[H₂SO₄] x Volume a = [KOH] x Volume b
-Solve for Volume b
Volume b = [H₂SO₄] x Volume a / [KOH]
-Substitution
Volume b = 7 x 12 / 3
-Simplification
Volume b = 28 ml
