Answer:
The probability that exactly 2 customers arrive in a given 5 minute interval = 0.2667
Step-by-step explanation:
Given -
The average number of customers arriving at an ATM machine is 27 per hour during lunch hours. then the average number of customers arriving at an ATM machine n a 5 minute time interval = [tex]\frac{27}{60} \times 5[/tex] = 2.25
average number of customers arriving at an ATM machine n a 5 minute time interval [tex](\lambda )[/tex] = 2.25
Let X denote the no of customer arrivals in a 5 minute time interval
The probability that exactly 2 customers arrive in a given 5 minute interval =
P( X = 2 ) = [tex]\frac{e^{-\lambda }\lambda ^{X}}{X!}[/tex] ( Using poision distribution )
= [tex]\frac{e^{-2.25} (2.25)^2}{2!}[/tex]
= [tex]\frac{.1054 \times 5.0625}{2}[/tex]
= 0.2667