Answer:
(a). Z = 54.54 ohm
(b). R = 36 ohm
(c). The circuit will be Capacitive.
Explanation:
Given data
I = 2.75 A
Voltage = 150 V
[tex]\phi = 0.85[/tex] rad = 48.72°
(a). Impedance of the circuit is given by
[tex]Z = \frac{V}{I}[/tex]
[tex]Z = \frac{150}{2.75}[/tex]
Z = 54.54 ohm
(b). We know that resistance of the circuit is given by
[tex]R = \frac{Z}{\sqrt{1 + \tan^{2}\phi } }[/tex]
Put the values of Z & [tex]\phi[/tex] in above formula we get
[tex]R = \frac{54.54}{\sqrt{1 + \tan^{2} ( \ 48.72) } }[/tex]
R = 36 ohm
(c). Since the phase angle is negative so the circuit will be Capacitive.
