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How much ice in grams would have to melt to lower the temperature of 360 mL of water from 45 ∘C to 0 ∘C? (Assume that the density of water is 1.0 g/mL.) Express your answer using two significant figures.

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Answer

203.7g

Explanation:

Heat gained= - heat lost

From the question

Mass of water = 360g

Heat capacity of water= 4.2Jg-1

Latent heat of ice= 334Jg-1

ml= -mcθ

m×334= -(360×4.2×(0-45))

334m= 68040

m= 68040/334

=203.7g

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