Respuesta :
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:
[tex]x+y=5600...(1)[/tex]
[tex]y=5600-x...(1)[/tex]
We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be [tex]40x[/tex] and cost of y end-zone tickets would be [tex]20y[/tex].
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:
[tex]40x+20y=134000...(2)[/tex]
Upon substituting equation (1) in equation (2), we will get:
[tex]40x+20(5600-x)=134000[/tex]
[tex]40x+112000-20x=134000[/tex]
[tex]20x+112000=134000[/tex]
[tex]20x+112000-112000=134000-112000[/tex]
[tex]20x=22000[/tex]
[tex]\frac{20x}{20}=\frac{22000}{20}[/tex]
[tex]x=1100[/tex]
Therefore, 1100 field side tickets were sold.
Upon substituting [tex]x=1100[/tex] in equation (1), we will get:
[tex]y=5600-1100[/tex]
[tex]y=4500[/tex]
Therefore, 4500 end-zone tickets were sold.
