Respuesta :
Answer: 841.46 V
Explanation:
Given
No of turns of primary coil, N1 = 320
No of turns of secondary coil, N2 = 2240
Max input voltage, Max ΔV(in) = 170 V
Max output voltage, Max ΔV(out) = ?
Rms voltage across the coil, ΔV(rms) = ?
Then to start, we find
Max ΔV(out) = N2/N1 * Max ΔV(in)
Max ΔV(out) = 2240 / 320 * 170
Max ΔV(out) = 7 * 170 = 1190 V
Now, ΔV(rms) = Max ΔV(out) / √2
ΔV(rms) = 1190 / √2
ΔV(rms) = 1190 / 1.4142
ΔV(rms) = 841.46 V
Therefore, the rms voltage developed across the secondary coil is 841.46 V
Answer:
The rms voltage across the secondary coil is 841.47 V
Explanation:
Given data:
N₁ = primary turns = 320
N₂ = secondary turns = 2240
From the input voltage
[tex]delta-V=170coswt[/tex]
V₁max = 170 V
The rms primary voltage is:
[tex]V_{1,rms} =\frac{V_{max} }{\sqrt{2} } =\frac{170}{\sqrt{2} } =120.21V[/tex]
[tex]\frac{N_{1}}{N_{2} } =\frac{V_{1}}{V_{2}} \\\frac{320}{2240} =\frac{120.21}{V_{2}} \\V_{2}=841.47V[/tex]
