Answer:
y=40
Step-by-step explanation:
If y varies jointly as a and b
y∝ab
If y varies inversely as the square root of c
y∝[tex]\frac{1}{\sqrt{c} }[/tex]
Combining the two
y∝[tex]\frac{ab}{\sqrt{c} }[/tex]
Introducing Variation Constant
[tex]y=\dfrac{kab}{\sqrt{c} }[/tex]
y=16, When a=4, b=5, c=25
[tex]16=\dfrac{k*4*5}{\sqrt{25} }\\16=\dfrac{20k}{5}\\20k=16*5\\20k=80\\k=4[/tex]
Therefore the equation connecting a. b and c is:
[tex]y=\dfrac{4ab}{\sqrt{c} }[/tex]
We are to determine y when a=5, b=4 and c=4
[tex]y=\dfrac{4*5*4}{\sqrt{4} }\\y=\dfrac{80}{2 }\\y=40[/tex]
Answer:
Y = 40
Step-by-step explanation:
When y varies jointly as a and b and inversely as the square root of c,we have an equation that looks like this
Y = kab/√c
Where k is the constant needed to get the proper values.
When Y is 6
A = 4,b = 5, and c = 25
16= (4 × 5 × k)/√25
16 = 20k/√25
Now cross multiply to get
16 × √25 = 20k
16 × 5 = 20k
80 = 20k
K = 4
So we now need to find Y when a is 5,b = 4 and = 4
Remember that k = 4
Y = kab/√c
Y = 4 × 5 × 4 ÷ √4
Y = 80÷2
Y = 40
