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in an arcade game, a 1.12 kg disk is shot across a frictionless horizontal surface by being compressed against a spring and then released. If the spring has a spring constant of 230 N/m and is compressed from the equilibrium position by 6.0 cm, what is the magnitude of the spring force ont he disk at the moment it is released?

Respuesta :

onyebuchinnaji

Answer:

The magnitude of the spring force on the disk at the moment it is released is 13.8 N

Explanation:

Given;

Mass of the disk, m = 1.12 kg

spring constant, k = 230 N/m

extension produced in the spring, x = 6.0 cm

According to Hook's law, the force applied to an elastic material is directly proportional to the extension produced.

F = kx

Where;

K is the spring constant

x is the extension of the spring

F = 230 x 0.06

F = 13.8 N

Therefore, the magnitude of the spring force on the disk at the moment it is released is 13.8 N

asuwafohjames

The magnitude of the spring force on the disk at the moment it is released is 13.8 N

 

To calculate the magnitude of the spring force on the disc, we the formula below.

Formula:

  • F = ke....................... Equation 1

Where:

  • k = Spring constant of the spring
  • e = Compression of the spring
  • F = magnitude of the spring force on the disc.

From the question,

Given:

  • k = 230 N/m
  • e = 6.0 cm = 0.06 m

Substitute these values into equation 1

  • F = 230(0.06)
  • F = 13.8 N

Hence, The magnitude of the spring force on the disk at the moment it is released is 13.8 N

Learn more about spring force here: https://brainly.com/question/26078393

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