Respuesta :
Answer:
A) d = 1.38 10-3 m, B) the velocity modulus remains constant and the velocity direction changes since the force is perpendicular
c) a = 1.94 10¹² m / s
d) the force is perpendicular to these two, that is, it points out of the page (positive z-axis)
e) E) the modulus of velocity remains constant because the force is perpendicular to the movement,
Explanation:
A) Let's use Newton's second law for this problem where the force is the magnetic force given by
F = m a
The magnetic force is
F = q v x B = q v B sin θ
Where the angle between the speed and the magnetite field is ce 90º so the sin 90 = 1
This implies that the acceleration is centripetal, which is given by
a = v² / R
We substitute
q v B = m v² / r
r = m v / qB
Let's calculate
r = 6.64 10⁻²⁷ 36.6 10³ / (2 1.6 10⁻¹⁹ 1.10)
r = 6,904 10⁻⁴ m
Diameter is twice the radius
d = 2 r
d= 1.38 10-3 m
B) The effect of the magnetic field is that the particle describes a circular motion, where the velocity modulus remains constant and the velocity direction changes since the force is perpendicular
C) the centripetal acceleration is
F = m a
q v B = m a
a = q v B / m
Let's calculate
a = 2 1.6 10⁻¹⁹ 36.6 10³ 1.10 / 6.64 10⁻²⁷
a = 1.94 10¹² m / s
D) Acceleration has the same direction of force toward the center of the circular orbit,
If we assume that the horizontal direction of the alpha particle is on the x-axis, the field is on the positive y-axis, so the force is perpendicular to these two, that is, it points out of the page (positive z-axis)
E) the modulus of velocity remains constant because the force is perpendicular to the movement, but the direction of the velocity does change in the direction of the force
A) The diameter is , [tex]d = 1.38*10^{-3} m[/tex],
B) The velocity modulus remains constant and the velocity direction changes since the force are perpendicular
C) The magnitude of the acceleration is, [tex]a = 1.94*10^{12} m / s[/tex]
D) The force is perpendicular to these two, that is, it points out of the page (positive z-axis)
E) The modulus of velocity remains constant because the force is perpendicular to the movement,
Newton's second law:
F = m a
The magnetic force is
F = q v x B = q v B sin θ
Where the angle between the speed and the magnetitc field is 90º so the sin 90 = 1
This implies that the acceleration is centripetal, which is given by
a = v² / R
q v B = m v² / r
r = m v / qB
On Subsituting the values:
r = 6.64* 10⁻²⁷ 36.6* 10³ / (2 *1.6 10⁻¹⁹ 1.10)
r = 6,904 *10⁻⁴ m
d = 2 r
d= 1.38 *10-3 m
B) The effect of the magnetic field is that the particle describes a circular motion, where the velocity modulus remains constant and the velocity direction changes since the force is perpendicular
C) The centripetal acceleration is
F = m a
q v B = m a
a = q v B / m
On subsituting:
a = 2 *1.6 10⁻¹⁹ 36.6 *10³ 1.10 / 6.64* 10⁻²⁷
a = 1.94* 10¹² m / s
D) Acceleration has the same direction of force toward the center of the circular orbit,
If we assume that the horizontal direction of the alpha particle is on the x-axis, the field is on the positive y-axis, so the force is perpendicular to these two, that is, it points out of the page (positive z-axis)
E) The modulus of velocity remains constant because the force is perpendicular to the movement, but the direction of the velocity does change in the direction of the force.
Find more information about Newton's second law here:
brainly.com/question/12970081
