A rectangular page in a textbook (with width w and length l) has an area of 98in2 , top and bottom margins set at 1 inch, and left and right margins at 1 2 inch. The printable area of the page is the rectangle that lies within the margins. What are the dimensions of the page that maximize the printable area?

Respuesta :

Answer:

Length = 14 in, width = 7 in

Step-by-step explanation:

The area of the page [tex]= l \times w = 98[/tex]

[tex]lw = 98[/tex]

The length of the printable area is gotten by subtracting the top and bottom margins from the length of the page [tex]= l - 1 - 1 = l - 2[/tex]

The width of the printable area is gotten by subtracting the left and right margins from the width of the page [tex]w - \frac{1}{2}- \frac{1}{2} = w-1[/tex]

The area of the printable area is

[tex]A = (l-2)(w-1) = lw - l - 2w + 2[/tex]

But [tex]lw = 98[/tex],

[tex]A = 98-l-2w+2 = 100-l-2w[/tex]

Also, from [tex]lw = 98[/tex],

[tex]l = \dfrac{98}{w}[/tex]

[tex]A = 100 - \dfrac{98}{w} - 2w[/tex]

To maximize this area,

[tex]\dfrac{dA}{dw} = 0[/tex]

[tex]\dfrac{98}{w^2} - 2 = 0[/tex]

[tex]\dfrac{98}{w^2} = 2[/tex]

[tex]2w^2 = 98[/tex]

[tex]w^2=49[/tex]

[tex]w=7[/tex]

Hence,

[tex]l = \dfrac{98}{7}=14[/tex]