Answer:
0.54704 is the probability that the company will receive atleast 8 calls.
Step-by-step explanation:
We are given the following information in the question:
Mean number of calls = 8 calls per hour
[tex]\lambda=8[/tex]
The distribution of calls Hot Line receives can be treated as a Poisson distribution.
We have to find the probability that the company will receive at least 8 calls
Formula:
[tex]P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}[/tex]
P(atleast 8) =
[tex]P( x \geq 8) =1 - P(x < 8)\\\\=1 - \displaystyle\sum_{x=0}^{x=7} \displaystyle\frac{\lambda^x e^{-\lambda}}{x!}\\\\ =1-0.45296\\\\= 0.54704[/tex]
Thus, 0.54704 is the probability that the company will receive atleast 8 calls.
