Answer:
exit temperature 285 K
Explanation:
given data
temperature T1 = 270 K
velocity = 180 m/s
exit velocity = 48.4 m/s
solution
we know here diffuser is insulated so here heat energy is negleted
so we write here energy balance equation that is
0 = m (h1-h2) + m × [tex](\frac{v1^2}{2}-\frac{v2^2}{2})[/tex] .....................1
so it will be
[tex]h1 + \frac{v1^2}{2} = h2 + \frac{v2^2}{2}[/tex] .....................2
put here value by using ideal gas table
and here for temperature 270K
h1 = 270.11 kJ/kg
[tex]270.11 + \frac{180^2\times \frac{1}{1000}}{2} = h2 + \frac{48.4^2\times \frac{1}{1000}}{2}[/tex]
solve it we get
h2 = 285.14 kJ/kg
so by the ideal gas table we get
T2 = 285 K