Answer:
The time taken by spider to catch insect 1.5 ms
Explanation:
Given:
Linear mass density [tex]\mu = 1 \times 10^{-5}[/tex] [tex]\frac{kg}{m}[/tex]
Tension on the string [tex]T = 0.40[/tex] N
Distance between web and insect lands [tex]x = 30 \times 10^{-2}[/tex] m
From the formula of velocity in string,
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
First find the velocity and then find time,
[tex]v = \sqrt{\frac{0.40}{1 \times 10^{-5} } }[/tex]
[tex]v = 200[/tex] [tex]\frac{m}{s}[/tex]
The time taken is given by,
[tex]v = \frac{x}{t}[/tex]
[tex]t = \frac{x}{v}[/tex]
[tex]t = \frac{30 \times 10^{-2} }{200}[/tex]
[tex]t = 1.5 \times 10^{-3}[/tex] sec
[tex]t = 1.5[/tex] ms
Therefore, the time taken by spider to catch insect 1.5 ms
