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. A telescope is constructed with two lenses separated by a distance of 25 cm. The focal length of the objective is 20 cm. The focal length of the eyepiece is 5 cm. Calculate the magnitude of the angular magnification of the telescope.

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Olajidey

Answer:

the magnitude of the angular magnification of the telescope. is 4

Explanation:

Calculate the magnitude of the angular magnification of the telescope.

Given that,

distance = 25cm

focal length from the objective f₀ = 20cm

focal length from eye piece f₁ = 5cm

The angular magnification of the telescope is

[tex]M = \frac{f_0}{f_1}[/tex]

Magnification = 20 / 5

magnification = 4

Hence, the magnitude of the angular magnification of the telescope. is 4

Lanuel

The angular magnification of this telescope is equal to 4.

Given the following data:

  • Distance = 25cm.
  • Focal length of eye piece = 5cm.
  • Focal length of the objective = 20cm.

How to calculate focal length.

Mathematically, the focal length of a telescope is given by this formula:

[tex]\frac{1}{f} =\frac{1}{u} +\frac{1}{v}[/tex]

Where:

  • f is the focal length of the lens.
  • u is the object distance.
  • v is the image distance from the lens.

In Science, the angular magnification of a telescope is given by this formula:

[tex]M = \frac{f_o}{f_1}[/tex]

Substituting the given parameters into the formula, we have;

[tex]M=\frac{20}{5}[/tex]

M = 4.

Read more on focal length here: https://brainly.com/question/23262564

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