Answer:
The force each wire experiences per unit length and what direction is the force are 2.1 x 10⁻⁴ N and repulsive.
Explanation:
given information:
the current of wire 1, I₁ = 3 A
the current of wire 2, I₂ = 7 A
the distance of two wire, r = 2 cm = 0.02 m
to find the force per unit length of each wire experience, we can use the
[tex]\frac{F}{l}[/tex] = μ₀ [tex]\frac{I_{1}I_{2} }{2\pi r}[/tex]
where
F = the magnetic force
I =current
r = the distance of the wire
μ₀ = permeability of vacuum (4π x 10⁻⁷ T.m/A)
thus,
[tex]\frac{F}{l}[/tex] = μ₀ [tex]\frac{I_{1}I_{2} }{2\pi r}[/tex]
= (4π x 10⁻⁷) [tex]\frac{(3)(7) }{2\pi (0.02)}[/tex]
= 2.1 x 10⁻⁴ N (Repulsive)
