5 women and 7 men are eligible to serve on a committee. If a committee of 4 is randomly selected, what is the probability that it will consist of 2 women and 2 men?

Respuesta :

Answer:

The required  probability is [tex]\frac{14}{33}[/tex].

Step-by-step explanation:

Probability:

The ratio of the favorable outcomes to the all possible outcomes.

Given that, 5 women and 7 men are eligible to serve on a committee.

A committee of 4 is randomly selected.

Choosing 2 women out of 5 women is

[tex]=^5C_2[/tex]

[tex]=\frac{5!}{2!(5-2)!}[/tex]

[tex]=\frac{5!}{2!3!}[/tex]

=10

Choosing 2 men out of 7 men is

[tex]=^7C_2[/tex]

[tex]=\frac{7!}{2!(7-2)!}[/tex]

[tex]=\frac{7!}{2!5!}[/tex]

=21

Total number of eligible person is = (5+7)=12

Choosing 4 member out of 12 member is

=[tex]^{12}C_4[/tex]

[tex]=\frac{12!}{4!(12-4)!}[/tex]

=495

The required  probability is

[tex]=\frac{10\times 21}{495}[/tex]

[tex]=\frac{14}{33}[/tex]