Answer: 67 seats
Step-by-step explanation:
Number of seats in row 2= 28
Number if seats in row 5 =37
This is a form of arithmetic progression.
Subtract the 2nd term from the 5th term. This will be:
a+4d= 37
-a+d = 28
3d= 9
d= 9/3
d= 3
Common difference is 3
Since d= 3, a will be
a+d = 28
a+3= 28
a= 28-3 = 25
Number of seats in row 15 will be:
a+14d
= 25+(14×3)
= 25 + 42
= 67
Row 15 has 67 seats
Answer:
67 seats
Step-by-step explanation:
We are going to use the arithmetic progression to solve this problem
remember that the the formula is
a + (n -1)d = n
Where n is the nth term
A is the first term
D is the difference
Apply the given variables into this equation and we have
In row 2 ,we have a total of 28 seats
And in row 5, we have 37 seats
This will lead to
a +(n - 1)d = 37 and here n is the 5th term so we have
a +4d = 37____ first equation
For row 2,
a + (n - 1)d = 28(remember that the nth term here is 2)
And we have
a + (2 - 1)d = 28 which is:
a + d = 28_____ equation 2
Now bring the 2 equations together and we have
a+4d= 37____ equation 1
a+d = 28_____ equation 2
Subtract the 2nd term from the 5th term. This will be:
3d= 9
d= 3
Common difference is 3
Since d= 3, a will be
a+d = 28
a+3= 28
a= 28-3 = 25
Therefore,the number of seats in row 15 will be
a+14d
= 25+(14×3)
= 25 + 42
= 67 seats in row 15
