Answer:
The frequency of coil must be 1.99 Hz
Explanation:
Given:
Magnetic field [tex]B = 0.50[/tex] T
Area of rectangular coil [tex]A = 0.14 \times 0.27 = 0.0378[/tex] [tex]m^{2}[/tex]
Maximum potential [tex]\epsilon _{max} = 130[/tex] V
Number of turns [tex]N = 550[/tex]
For finding the frequency we use faraday's law
Maximum induced emf in rectangular coil is given by,
[tex]\epsilon _{max} = NBA\omega[/tex]
Where [tex]\omega = 2\pi f[/tex]
[tex]\epsilon _{max} = NBA(2\pi f )[/tex]
[tex]f = \frac{\epsilon _{max} }{NBA2\pi }[/tex]
[tex]f = \frac{130}{550 \times 0.50 \times 0.0378 \times 6.28}[/tex]
[tex]f = 1.99[/tex] Hz
Therefore, the frequency of coil must be 1.99 Hz
