An airplane flew with the wind for 2.5 hours and returned the same distance against the wind in 3.5 hours. If the cruising speed of the plane was a constant 360 mph in air, how fast was the wind blowing

Respuesta :

Answer:

60 miles per hour.

Step-by-step explanation:

Let r represent speed of wind blowing in miles per hour.          

We have been given that the cruising speed of the plane was a constant 360 mph in air. The speed of the plane is the direction of wind would be [tex]360+r[/tex].

The speed of the plane is the opposite direction of wind would be [tex]360-r[/tex].

[tex]\text{Distance}=\text{Speed}\times \text{Time}[/tex]

Distance covered in the direction of wind would be [tex]2.5(360+r)[/tex].

Distance covered in the opposite direction of wind would be [tex]3.5(360-r)[/tex].

Since both distances are same, so we will get:

[tex]2.5(360+r)=3.5(360-r)[/tex]

[tex]900+2.5r=1260-3.5r[/tex]

[tex]900-900+2.5r+3.5r=1260-900-3.5r+3.5r[/tex]

[tex]6r=360[/tex]

[tex]\frac{6r}{6}=\frac{360}{6}[/tex]

[tex]r=60[/tex]

Therefore, the wind is blowing at a rate of 60 miles per hour.